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The behavior of REGEX when it did not match was not defined by the docs, so

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define it to provide a result of "0" and change the code appropriately.
(issue #7805)


git-svn-id: https://origsvn.digium.com/svn/asterisk/trunk@41544 65c4cc65-6c06-0410-ace0-fbb531ad65f3
This commit is contained in:
Russell Bryant
2006-08-31 04:07:35 +00:00
parent 6557d250c8
commit 42fc890acc
1 changed files with 6 additions and 6 deletions
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12
funcs/func_strings.c
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@@ -115,7 +115,7 @@ static int regex(struct ast_channel *chan, char *cmd, char *parse, char *buf,
int errcode;
regex_t regexbuf;
buf[0] = '\0';
buf[0] = '0';
AST_NONSTANDARD_APP_ARGS(args, parse, '"');
@@ -130,10 +130,10 @@ static int regex(struct ast_channel *chan, char *cmd, char *parse, char *buf,
regerror(errcode, &regexbuf, buf, len);
ast_log(LOG_WARNING, "Malformed input %s(%s): %s\n", cmd, parse, buf);
return -1;
} else {
if (!regexec(&regexbuf, args.str, 0, NULL, 0))
strcpy(buf, "1");
}
strcpy(buf, regexec(&regexbuf, args.str, 0, NULL, 0) ? "0" : "1");
regfree(&regexbuf);
return 0;
@@ -141,8 +141,8 @@ static int regex(struct ast_channel *chan, char *cmd, char *parse, char *buf,
static struct ast_custom_function regex_function = {
.name = "REGEX",
.synopsis =
"Regular Expression: Returns 1 if data matches regular expression.",
.synopsis = "Regular Expression",
.desc = "Returns 1 if data matches regular expression, or 0 otherwise.",
.syntax = "REGEX(\"<regular expression>\" <data>)",
.read = regex,
};